DW vs Bottomless

[Milo di Scorpio]

Hello,

Player A has Bottomless Trap Hole set
Player B play Graceful Charity and discard 2 Goldd
When Player A special summon Goldd, Player actives BTH...

...then both Goldd are removed or only the last Goldd special summoned?????

 

[SPK]

In this situation, when the 2 Goldds are discarded by the effect of Graceful Charity, their effects resolve one at a time:

1. Goldd
2. Goldd.

When resolving their effects, 1 Goldd will be special summoned, Player A cannot activate BTH at this point, since another effect is still resolving (the summoning of the 2nd Goldd). When the 2nd Goldd's effect is resolved, then the timing is correct to activate BTH, which will then RFG the last Goldd summoned...

With that said, if another effect was resolving as the last one (e.g. Broww), BTH would not be able to be activated, nor even a card such as TT, since the effect that last resolved, which Player A could respond to, was not the summon of a monster.

 

[Entropy]

Short answer: Only the last Golld summoned will be destroyed and removed.

Long answer: Both Gollds form a chain, according to SECOG.

Link 1: Golld #1
Link 2: Golld #2

Both Gollds will be Special Summoned, and you can activate Bottomless Trap Hole in response to Golld #1's summoning. However, it will only affect Golld #1 will be removed, since you missed the timing for Golld #2.

 

[Digital Jedi]

And let's be sure to clarify that this is only worling this way because it was discarded by your card effect, Graceful Charity.

If the two Goldds had been discarded by your opponent's card effect, then each Goldd's second effect would have activated. Regardless of being the last link in the chain, the destruction effect of the last Goldd would happen after he Special Summons, and would interupt the timing of Bottomless Trap Hole.